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The Most Affordable Vacation Destinations in the US

by Jori Ayers Sep 2, 2021

The COVID-19 pandemic is far from over, and with the Delta variant raging and the ever-changing travel restrictions, many want to keep their vacation destinations domestic rather than international.

To help you plan your next vacay, travel blog ParkSleepFly rounded up the most affordable urban vacation destinations in the US. The ranking was based on the average cost of a hotel stay for a weekend, food and drink, and transportation (taxi and public transport), in 51 US cities.

Oklahoma City, OK, came in as the most affordable vacation destination. It scored 8.58 out of 10 for affordability with beer only costing $3; $11.50 for a meal at a restaurant; and only $106 for a hotel night. Indianapolis came in second with a vacation affordability score of 8 out of 10.

The most affordable vacation destinations in the US:

  1. Oklahoma City, OK — 8.58/10
  2. Indianapolis, IN — 8/10
  3. Tucson, AZ — 7.96/10
  4. Memphis, TN — 7.87/10
  5. San Antonio, TX — 7.77/10

New York City tops the list of the least affordable urban vacation destination in the US. The average cost of a weekend hotel stay is $309 per night, $20 for a meal, and $7.81 for a beer. New York City’s vacation affordability score is 2.56 out of 10. San Francisco is not far behind with a score of 3.07 out of 10.

The least affordable destinations in the US:

  1. New York City, NY– 2.56/10
  2. San Francisco, CA — 3.07/10
  3. Boston, MA — 3.16/10
  4. Brooklyn, NY — 3.7/10
  5. Philadelphia, PA — 3.94/10

For the full list of the 51 most affordable and most expensive urban vacation destinations in the US, and to learn more about the methodology behind the ranking, check out ParkSleepFly’s website.

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