If you’re looking for a luxurious five-star hotel, it might not be worth it to break the bank. If you have some flexibility with your destination, you could get that luxury experience in one of the world’s cheapest five-star hotels.

LuxuryHotel.com recently conducted research and rounded up the most expensive, and thankfully also the cheapest, five-star hotels. The study judged cities in over 100 countries and found the average price rounded out to about $236 per night. The luxurious city of Abu Dhabi offers the most five-star experiences, as 32 percent of the country’s hotels and resorts are rated five stars.

Claiming the top spot for the most expensive stay in the world is in the United States. A hotel in Los Angeles will run you an average of $675 per night. Paris, the city of romance, will cause a breakup with you and your wallet at $664 per night. In Orlando, expect to spend an average of $663. Other US cities in the top ten include Honolulu and Miami.

  • Los Angeles, USA — $675.84
  • Paris, France — $664.53
  • Orlando, USA — $663.11
  • Honolulu, USA — $585.35
  • Rome, Italy — $558.49
  • Venice, Italy — $518.90
  • Florence, Italy — $493.45
  • Miami, USA — $477.89
  • Milan, Italy — $473.65
  • Toronto, Canada — $472.24

That being said, if you’d like to get the best bang for your buck then take a trip to India, where the cities are home to seven out of 10 of the cheapest five-star hotels. You can get a room in Chennai, India, for as low as $47 per night. In India, Johor Bahru, Malaysia, and Bangalore tie for second place at $57 per night.

Here are the cheapest cities for a five-star luxury stay worldwide.

  • Chennai, India — $47
  • Johor Bahru, Malaysia — $57
  • Bangalore, India — $57
  • Agra, India — $58
  • Kolkata, India — $69
  • New Deli, India — $69
  • Mumbai, India — $72
  • Jaipur, India — $78
  • Phuket, Thailand — $79
  • Cebu, Philippines — $79

Wherever you decide to go, you might want to reference the full study to make sure you’re getting the most for your money.