The Cheapest and Most Expensive Cities to Stay in a 5-Star Hotel

Claiming the top spot for the most expensive stay in the world is in the United States. A hotel in Los Angeles will run you an average of $675 per night. Paris, the city of romance, will cause a breakup with you and your wallet at $664 per night. In Orlando, expect to spend an average of $663. Other US cities in the top ten include Honolulu and Miami.

• Los Angeles, USA — $675.84
• Paris, France — $664.53
• Orlando, USA — $663.11
• Honolulu, USA — $585.35
• Rome, Italy — $558.49
• Venice, Italy — $518.90
• Florence, Italy — $493.45
• Miami, USA — $477.89
• Milan, Italy — $473.65
• Toronto, Canada — $472.24

That being said, if you’d like to get the best bang for your buck then take a trip to India, where the cities are home to seven out of 10 of the cheapest five-star hotels. You can get a room in Chennai, India, for as low as $47 per night. In India, Johor Bahru, Malaysia, and Bangalore tie for second place at $57 per night.

Here are the cheapest cities for a five-star luxury stay worldwide.

• Chennai, India — $47
• Johor Bahru, Malaysia — $57
• Bangalore, India — $57
• Agra, India — $58
• Kolkata, India — $69
• New Deli, India — $69
• Mumbai, India — $72
• Jaipur, India — $78
• Phuket, Thailand — $79
• Cebu, Philippines — $79

Wherever you decide to go, you might want to reference the full study to make sure you’re getting the most for your money.